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8k^2+80k+168=0
a = 8; b = 80; c = +168;
Δ = b2-4ac
Δ = 802-4·8·168
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-32}{2*8}=\frac{-112}{16} =-7 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+32}{2*8}=\frac{-48}{16} =-3 $
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